[Lustre-discuss] lfs df vs. df -k

[Andreas Dilger]

On Oct 13, 2008  13:42 -0500, Hendelman, Rob wrote:
> Total space available: df -k and lfs df show the exact same # of 1k
> blocks.  So far so good.  However, a df -k shows 4783238028 1k blocks in
> use, while a lfs df shows 5399853568 1k blocks in use.  Interestingly,
> lfs df -i and df -i both show the same number of total inodes the same.
> They ALSO both show the used inodes the same as well.  Free inodes are
> also the same.  Everything matches.
> 
> Anyone know why "df -k" used space doesn't match between "lfs df -k" and
> df -k ?
> 
> Client is 2.6.22 patchless kernel/client on Ubuntu.  The server is
> centos using the packages provided for download, including kernel:
> 
> -bash-3.1$ rpm -qa | sort | grep lust
> kernel-lustre-smp-2.6.18-53.1.13.el5_lustre.1.6.4.3
> lustre-1.6.4.3-2.6.18_53.1.13.el5_lustre.1.6.4.3smp
> lustre-ldiskfs-3.0.4-2.6.18_53.1.13.el5_lustre.1.6.4.3smp
> lustre-modules-1.6.4.3-2.6.18_53.1.13.el5_lustre.1.6.4.3smp

It's a bug that was fixed - we were printing blocks in use based on "free"
instead of "available" blocks, or something similar.  Sorry, I don't have
the bug number handy.

Cheers, Andreas
--
Andreas Dilger
Sr. Staff Engineer, Lustre Group
Sun Microsystems of Canada, Inc.